Skip to content

[★★★☆☆] Lee's Frame

The Lee's frame is shown as follows.

Lee's frame

The model can be downloaded. lees-frame.supan

Model Setup

Since this is an elastic analysis, we use EB21 element to model this problem. To suppress axial deformation, a large area of \(500\) is assigned. The node and element definitions can be established as follows.

Text Only
node 1 0 0
node 2 0 1
node 3 0 2
node 4 0 3
node 5 0 4
node 6 0 5
node 7 1 5
node 8 2 5
node 9 3 5
node 10 4 5
node 11 5 5

element EB21 1 1 2 500. 1. 1 1
element EB21 2 2 3 500. 1. 1 1
element EB21 3 3 4 500. 1. 1 1
element EB21 4 4 5 500. 1. 1 1
element EB21 5 5 6 500. 1. 1 1
element EB21 6 6 7 500. 1. 1 1
element EB21 7 7 8 500. 1. 1 1
element EB21 8 8 9 500. 1. 1 1
element EB21 9 9 10 500. 1. 1 1
element EB21 10 10 11 500. 1. 1 1

material Elastic1D 1 10

fix 1 1 1 11
fix 2 2 1 11

Both snap-back and snap-through are involved in this example, the arc length method shall be used. A reference load of magnitude \(-1\) is applied on the DoF 2 of node 7.

Text Only
step arclength 1 7 2 -1

Here the magnitude of reference load matters. A proper selection of reference load may help to converge. The algorithm automatically scale the arc length so a stopping criterion shall be applied. If no solver is defined. To customize the solving strategy, it is possible to define a Ramm solver.

Text Only
solver Ramm 1 .05 true
set max_iteration 1000

The above command defines a Ramm solver using a fixed arc length of \(0.5\). By default, a maximum of \(1000\) sub steps are allowed, this may not be sufficient, to change it the set command can be called.

Text Only
criterion MinDisplacement 1 7 2 -3.8

With the above criterion, when the negative displacement of DoF2 of node 7 reaches \(-3.8\), the analysis stops.

Now the model can be analyzed.

Text Only
analyze

Result

example one

The sign of vertical displacement is flipped.